Subset sum problem (Minimum)
(Mylib/Typical/subset_sum_minimum.cpp)
Operations
-
subset_sum_minimum(N, K, a[N])
- 和が
K
になる部分集合の最小サイズ。そのような部分集合が存在しないとき-1を返す。
- Time complexity $O(NK)$
Requirements
Notes
Problems
References
Code
#pragma once
#include <algorithm>
#include <cassert>
#include <climits>
#include <vector>
namespace haar_lib {
auto subset_sum_minimum(int N, int K, const std::vector<int> &a) {
assert((int) a.size() == N);
std::vector<std::vector<int64_t>> dp(2, std::vector<int64_t>(K + 1, INT_MAX));
dp[0][0] = 0;
for (int i = 0; i < N; ++i) {
for (int j = 0; j <= K; ++j) {
if (j >= a[i])
dp[(i + 1) & 1][j] = std::min(dp[i & 1][j - a[i]] + 1, dp[i & 1][j]);
else
dp[(i + 1) & 1][j] = dp[i & 1][j];
}
}
for (int i = 0; i <= K; ++i) {
if (dp[N & 1][i] == INT_MAX) dp[N & 1][i] = -1;
}
return dp[N & 1];
}
} // namespace haar_lib
#line 2 "Mylib/Typical/subset_sum_minimum.cpp"
#include <algorithm>
#include <cassert>
#include <climits>
#include <vector>
namespace haar_lib {
auto subset_sum_minimum(int N, int K, const std::vector<int> &a) {
assert((int) a.size() == N);
std::vector<std::vector<int64_t>> dp(2, std::vector<int64_t>(K + 1, INT_MAX));
dp[0][0] = 0;
for (int i = 0; i < N; ++i) {
for (int j = 0; j <= K; ++j) {
if (j >= a[i])
dp[(i + 1) & 1][j] = std::min(dp[i & 1][j - a[i]] + 1, dp[i & 1][j]);
else
dp[(i + 1) & 1][j] = dp[i & 1][j];
}
}
for (int i = 0; i <= K; ++i) {
if (dp[N & 1][i] == INT_MAX) dp[N & 1][i] = -1;
}
return dp[N & 1];
}
} // namespace haar_lib
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